Question

Rationailze the denominator in the following
$\frac{1}{ \sqrt{7} - \sqrt{6} }$
​

Answer 1

$\frac{1}{ \sqrt{7} - \sqrt{6} } = \frac{1}{ \sqrt{7} - \sqrt{6} } \times \frac{ \sqrt{7} + \sqrt{6} }{ \sqrt{7} + \sqrt{6} }$

$= \frac{ \sqrt{7} + \sqrt{6} }{ \sqrt{ {7}^{2} } - \sqrt{ {6}^{2} } } = \sqrt{7} + \sqrt{6}$

Hope it helps you

Mark as brainliest and follow me

Answer 2

$\bf \huge \red{Question : - }$

Rationalize the denominator!!!

1/√7-√6

$\bf \huge \red{Solution : - }$

$\bf \large\implies \: \frac{1}{ \sqrt{7} - \sqrt{6} } \\ \\ \bf \large\implies \: \frac{1}{ \sqrt{7} - \sqrt{6} } \times \frac{ \sqrt{7} + \sqrt{6} }{ \sqrt{7} + \sqrt{6} } \\ \\ \bf \large\implies \: \frac{ \sqrt{7} + \sqrt{6} }{ {( \sqrt{7} })^{2} - {( \sqrt{6} })^{2} } \\ \\ \bf \large\implies \: \frac{ \sqrt{7} + \sqrt{6} }{7 - 6} \\ \\ \bf \large\implies \: \frac{ \sqrt{7} + \sqrt{6} }{1} \\ \\ \bf \large\implies \: \sqrt{7} + \sqrt{6}$