Question

Rationaise the denominator of 1/√5+√2

Answer 1

1/√5+√2 ×√5-√2/√5-√2

√5-√2/[√5]^2-[√2]^2. [a+b][a-b]=a^2-b^2

√5-√2/5-2

√5-√2/3

The rationalising factor is √5-√2/√5-√2

Answer 2

Answer:

1/√5+√2*√5-√2/√5-√2

√5-√2/√5 square-√2square

√5-√2/5-2

√5-√2/3

I hope you understand