Question

Rational ise the denominators 1/√7-√6

Answer 1

Answer:

Given \frac{1}{\sqrt{7}- \sqrt{6}}

Multiplynumerator and denominator by(√7+√6),weget

= \frac{(\sqrt{7}+\sqrt{6})}</p><p>{(\sqrt{7}-\sqrt{6})(\sqrt{7}+\sqrt{6})}

\*Byalgebraic identity:

(a+b)(a-b)=a²-b²

= \frac{(\sqrt{7}+\sqrt{6})}{(\sqrt{7})^{2}-(\sqrt{6})^{2}}

= \frac{(\sqrt{7}+\sqrt{6})}{7-6}

= (\sqrt{7}+\sqrt{6})

Therefore,

\frac{1}{\sqrt{7}- \sqrt{6}}= (\sqrt{7}+\sqrt{6})

Answer 2

Step-by-step explanation:

on rationalising the denominator

1/ √7 -√6 × √7+ √6 / √7+√6

√7+ √6 / √7 square - √6square

√7+√6/ 7-6

√7+ √6 / 1

hope this will help u