Math, asked by basvarajramchandra, 18 days ago

Rational numbers are not closed under

A.addition B.subtration
C.multiplication C.division​

Answers

Answered by Hyemi2008
9

Answer:

Rational numbers are not closed under division

Answered by jeon36491
14

Answer:

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Related Questions

Rational numbers are closed under ……….

(a) addition

(b) subtraction

(c) multiplication

(d) all of the above

Answer

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Hint: Here, we will check whether the rational numbers are closed under the given operations or not. A set is closed under an operation if performance of that operation on members of the set always produces a member of that set.

Complete step-by-step answer:

A rational number is a number that can be expressed as the quotient or fraction pq of two integers, a numerator p and a non-zero denominator q. Since, q may be equal to 1, every integer is a rational number. The set of all rational numbers, often referred to as ‘ the field of rationals’ is usually denoted by Q .

A set that is closed under an operation or collection of operations is said to satisfy a closure property. Often a closure property is introduced as an axiom, which is then usually called the axiom of closure.

For any two rational numbers, say x and y, the results of addition, subtraction and multiplication operations give a rational number. Division is not under closure property because division by zero is not defined.

For example, if we take two rational numbers 12 and 34, then:

12 +34=1×2+3×14=2+34=54, which is a rational number.

Also, 12 -34=1×2−3×14=2−34=−14, which is a rational number.

And, 12×34=38, which is also a rational number.

Thus, we see that for addition, subtraction as well as multiplication, the result that we get is itself a rational number. This means that rational numbers are closed under addition, subtraction and multiplication.

Hence, option (d) is the correct answer.

Note: Students should remember the meaning of the closure property. One should also note that the denominator of a rational number can never be 0 otherwise it will not be defined.

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