Question

rational the denominatir of 3-root2 by 3 +root2​

Answer 1

Answer:

$\frac{11 - 6 \sqrt{2} }{7}$

Solution:-

$\frac{3 - \sqrt{2} }{3 + \sqrt{2} }$

$\frac{3 - \sqrt{2} }{3 + \sqrt{2} } \times \frac{3 - \sqrt{2} }{3 - \sqrt{2} }$

$\frac{ ({3 - \sqrt{2} })^{2} }{ {(3)}^{2} - {( \sqrt{2}) }^{2} }$

We know that (a-b)^2=a^2 -ab +b^2

So;

$\frac{ {(3)}^{2} - 2 \times 3 \times \sqrt{2} + {( \sqrt{2}) }^{2} }{9 - 2}$

$\frac{9 - 6 \sqrt{2} + 2 }{7}$

$\frac{11 - 6 \sqrt{2} }{7}$

Answer 2

Answer:

Hope it help you !!!!!!!