Question

rational the denominator and simplify: 2√3-√5 by 2√2+3√3

Answer 1

2√3-√5/2√2+3√3

Rationalising factor = 2√2-3√3

→ (2√3-√5)/(2√2+3√3) × (2√2-3√3)/(2√2-3√3)

→ 2√3-√5(2√2-3√3)/(2√2+3√3)(2√2-3√3)

→ 2√3(2√2-3√3)-√5(2√2-3√3)/{(2√2)²-(3√3)²}

→ 4√6-6(3)-2√10+3√15/{4(2)-9(3)}

→ 4√6-18-2√10+3√15/(8-27)

→ 4√6-18-2√10+3√15/(-19)

→ -(4√6-2√10+3√15-18)/19

→ (-4√6+2√10-3√15+18)/19

Hope it helps…