Question

rationalies the denominator of (√3-√2)÷(√3+√2)

​

Answer 1

Answer:

= 5 - 2√6

Step-by-step explanation:

$=> \frac{\sqrt{3}-\sqrt{2}}{\sqrt{3}+\sqrt{2}} \\\\ rationalising \ factor=\sqrt{3}-\sqrt{2} \\\\ => \frac{\sqrt{3}-\sqrt{2}}{\sqrt{3}+\sqrt{2}} \times \frac{\sqrt{3}-\sqrt{2}}{\sqrt{3}-\sqrt{2}} \\\\ => \frac{(\sqrt{3}-\sqrt{2})(\sqrt{3}-\sqrt{2})}{(\sqrt{3}+\sqrt{2})(\sqrt{3}-\sqrt{2})} \\\\ => \frac{(\sqrt{3}-\sqrt{2})^2}{(\sqrt{3}^2-\sqrt{2}^2)} \\\\ => \frac{\sqrt{3}^2+\sqrt{2}^2-2(\sqrt{3})(\sqrt{2})}{3-2} \\\\ => \frac{3+2-2\sqrt{6}}{1} \\\\ => 5-2\sqrt{6} \\ ---------- \\ \textbf{FORMULA USED:}$

$(a+b)(a-b)=a^2-b^2 \\ (a-b)^2=a^2+b^2-2ab$

hope it helps..!

Answer 2

Answer:

hope it helps you.....