Question

Rationalisation of denominator​

Answer 1

Answer:

2-√3

Step-by-step explanation:

$\frac{ \sqrt{3} - 1}{ \sqrt{3} + 1 } \\ = \frac{ \sqrt{3} - 1}{ \sqrt{3} + 1 } \times \frac{ \sqrt{3} - 1}{ \sqrt{3} - 1 } \\ = \frac{( {\sqrt{3} - 1)}^{2} } { (\sqrt{3} + 1)(\sqrt{3} - 1)} \\ = \frac{4 - 2 \sqrt{3} }{2} \\ = 2 - \sqrt{3}$

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