Math, asked by vanshikasingh83, 1 year ago

rationalisation the question.​

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Answered by mitajoshi11051976
1
 = \frac{5 + \sqrt{3} }{7 + \sqrt[4]{3} } \\ \\ = \frac{5 + \sqrt{3} }{7 + \sqrt[4]{3} } \times \frac{7 - \sqrt[4]{3} }{7 - \sqrt[4]{3} } \\ \\ =


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Answered by Abhinavsingharmy10
0

Answer:

Step-by-step explanation:

5+2root3/7+4root3 ×7-4root3/7-4root3

5(7-4root3) × 2root3(7-4root3)/(7)² - (4root3)²

11-6 root3

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