Rationalise
1
2+
![\sqrt{3} \sqrt{3}](https://tex.z-dn.net/?f=+%5Csqrt%7B3%7D+)
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2
Answer:
1 /2+√3
= 1(2-√3)/(2+√3)(2-√3)
= 2-√3/(2)^2 - (√3)^2
= 2-√3/4 - 3
= 2-√3
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