Question

rationalise 1/3+2√2​

Answer 1

$\huge\bf{\red{Solution:-}}$

Rationalise

$\sf\bullet \dfrac{1}{3+2\sqrt{2}}$

Rationalize it by denominator

$\sf\implies \dfrac{1}{3+2\sqrt{2}}\times \dfrac{(3-2\sqrt{2})}{(3-2\sqrt{2})}\\ \\ \sf\implies \dfrac{3-2\sqrt{2}}{(3){}^{2}-(2\sqrt{2}){}^{2}}\\ \\ \sf\implies \dfrac{3-2\sqrt{2}}{9-8}\\ \\ \sf\implies \dfrac{3-2\sqrt{2}}{1}\\ \\ \sf\implies or\:\:\: 3-2\sqrt{2}$

Answer 2

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❏ Question:-

Rationalise the

$\sf{\ \ {\dfrac{1}{3+2\sqrt{2}}}}$

❏ Solution:-

$\implies\sf{\ \ {\dfrac{1}{3+2\sqrt{2}}}}$

$\implies\sf{\ \ {\dfrac{1(3-2\sqrt{2})}{(3+2\sqrt{2})(3-2\sqrt{2})}}}$

$\implies\sf{\ \ {\dfrac{(3-2\sqrt{2}}{3^2-(2\sqrt{2})^2}}}$

$\implies\sf{\ \ {\dfrac{(3-2\sqrt{2}}{(9-8)}}}$

$\implies\sf{\ \ {\dfrac{(3-2\sqrt{2}}{(1)}}}$

$\implies\boxed{\sf{\ \ {(3-2\sqrt{2})}}}$

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