Math, asked by Anonymous, 1 year ago

Rationalise ...

1/√5 - 3

...............

Answers

Answered by alinasharma
4

 \frac{1}{ \sqrt{5}  - 3}  \\  \\  =  \geqslant  \frac{1}{ \sqrt{5}  - 3}  \times  \frac{ \sqrt{5} + 3 }{ \sqrt{5}  + 3}  \\  \\  =  \geqslant  \frac{ \sqrt{5}  + 3}{ \sqrt{5 {}^{2} }  -  {3}^{2} }  \\  \\  =  \geqslant  \frac{ \sqrt{5}  + 3}{5 - 9}  \\  \\  =  \geqslant  \frac{ \sqrt{5} + 3 }{ - 4}  \\  \\  =  \geqslant  \frac{ - ( \sqrt{5} + 3) }{4}  \\  \\  =  \geqslant  \frac{ -  \sqrt{5}  -  \sqrt{3} }{4}


Anonymous: sorry
alinasharma: xD ok
Answered by Anonymous
7

RATIONALISE\: ..

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alinasharma: nice
shubham04031994: nice
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