Question

Rationalise 1/5+3*root2

Answer 1

$\displaystyle \Longrightarrow\ \frac{1}{5+3\sqrt{2}} \\ \\ \\ \\ \Longrightarrow\ \frac{1(5-3\sqrt{2})}{(5+3\sqrt{2})(5-3\sqrt{2})} \\ \\ \\ \\ \Longrightarrow\ \frac{5-3\sqrt{2}}{(5)^2-(3\sqrt{2})^2} \\ \\ \\ \\ \Longrightarrow\ \frac{5-3\sqrt{2}}{25-18} \\ \\ \\ \\ \Longrightarrow\ \frac{5-3\sqrt{2}}{7}$

Thus rationalized the fraction.

As the denominator is 5+3√2, multiply each the numerator and the denominator by 5-3√2. Thus the numerator becomes 5-3√2 and the denominator becomes 25 - 18 = 7 according to (a +b)(a - b) = a² - b².

Thus the denominator will be rationalized.

Answer 2

Answer:

Step-by-step explanation:

Here is ur answer dear!!

By shubhangi