Rationalise 1 + root 3 by 1 minus root 3
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(1+√3)/1-√3
=(1+√3)(1+√3)/(1-√3)*(1+√3)
=(1+2√3+3)/1-3
=-(4+2√3)/2
=-2(2+√3)/2
=-2-√3
Answered by
1
Answer:
1+root3/1-root3
(1+root3/1-root3)×(1+root3/1+root3)
(1+root3)^2/(1-root3^2)
(1+root3^2+2.root3)/(1-root3^2)
(1+3+2root3)/(1-3)
(4+2root3)/(-2)
2 (2+root3)/(-2)
-(2+root3)
-2-root3
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