Question

Rationalise 1/ root3 - 1
​

Answer 1

Answer:

Here your answer is given

Answer 2

✍️Question:-

$\implies \tt \Rationalise \dfrac{1}{\sqrt{3}-1}$

$\rule{300}{1}$

✍️How to solve?

• Multiply numerator and denominator by a radical that will get rid of the denominator radical.
• Make sure all radicals are simplified.
• Simplified the fraction needed.

☀️So, lets start.

✍️Solution:-

$\implies \dfrac{1}{\sqrt{3}-1} \\\\ \tt \Multiply\:and\:divide\:by\: \sqrt{3}+1 \\\\ = \dfrac{1}{\sqrt{3}-1} \times \dfrac{\sqrt{3}+1}{\sqrt{3}+1} \\\\ = \dfrac{\sqrt{3}+1}{\sqrt{3}-1}\\\\ =\dfrac{\sqrt{3}+1}{2}$

✍️Answer:-

$\bf {\boxed {\boxed {\tt {\red {Answer = \dfrac{\sqrt{3}+1}{2}}}}}}$

☃️Hence, we are completed with the problem.