rationalise 1/root5+root3-root2
Answers
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Answer:
1 = -4(√5+√3-√2)-2(√30+3√2-2√3)
√5+√3-√2 8
Step-by-step explanation:
1 => 1 × √5-(√3-√2) = √5-(√3-√2)
√5+√3-√2 √5+(√3-√2) √5-(√3-√2) (√5)²-(√3-√2)²
1 => √5+√3-√2
√5+√3-√2 (√5)²-(√3)²+(√2)²-2(√3)(√2)
1 => √5+√3-√2 = √5+√3-√2
√5+√3-√2 5-3+2-2√6 4-2√6
1 => (√5+√3-√2) × (4+2√6)
√5+√3-√2 4-2√6 4+2√6
1 =>4(√5+√3-√2)+2√30+2√18-2√12
√5+√3-√2 (4)²-(2√6)²
1 =>4(√5+√3-√2)+2√30+2×3√2-2×2√3
√5+√3-√2 16 -24
1 => -[4(√5+√3-√2)+2(√30+3√2-2√3)]
√5+√3-√2 8