rationalise 2√3-√3/2 √2+ 3√3
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3
Answer:
We rationalise the denominator of (
3
−
2
3
+
2
) by multiplying its rationalising factor (
3
+
2
) in the numerator and denominator as follows:
3
−
2
3
+
2
×
3
+
2
3
+
2
=
(
3
−
2
)(
3
+
2
)
(
3
+
2
)(
3
+
2
)
=
(
3
)
2
−(
2
)
2
(
3
+
2
)
2
=
3−2
(
3
)
2
+(
2
)
2
+(2×
3
×
2
)
=
1
3+2+2
6
=5+2
6
Hence,
3
−
2
3
+
2
=5+2
6
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