Question

rationalise √2+√3/3√2-2√3​

Answer 1

Solution :

Given √2+√3/3√2-2√3

= (2+√3/3√2-2√3)[(3√2+2√3)/(3√2+2√3)]

= [6√2+4√3+3√6+6]/[(3√2)²-(2√3)²]

= ( 6+6√2+4√3+3√6)/(18-12)

=( 6+6√2+4√3+3√6)/6

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Answer 2

Answer:

$\sqrt{2}+\frac{\sqrt{3} }{3\sqrt{2} }-2\sqrt{3}=\frac{\sqrt{6 }+6\sqrt{2}  }{6}-2\sqrt{3}=-1.641639762$

Step-by-step explanation: