Question

rationalise 2+√3/√6-2​

Answer 1

Step-by-step explanation:

$\frac{2 + \sqrt{3} }{ \sqrt{6} - 2 } = \frac{2 + \sqrt{3} }{ \sqrt{6} - 2} \times \frac{ \sqrt{6} + 2}{ \sqrt{6} + 2 } = \frac{2 \sqrt{6} + 4 + \sqrt{18} + 2 \sqrt{3} }{6 - 4} = \frac{4 + 2 \sqrt{6} + 3 \sqrt{2} + 2 \sqrt{3} }{2}$

Answer 2

bro here it's your answer