Math, asked by sajum4995, 16 days ago

Rationalise : 2− √5 2+3√5​

Answers

Answered by raj8825222129
0

Answer:

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Answered by anubhabkumar2020
0

Answer:

Answer:

Answer: It is already rationalised

Answer: It is already rationalised Step-by-step explanation:

Answer: It is already rationalised Step-by-step explanation:Have to a good day ahead

Answer: It is already rationalised Step-by-step explanation:Have to a good day ahead

Answer: It is already rationalised Step-by-step explanation:Have to a good day ahead L=2m,

Answer: It is already rationalised Step-by-step explanation:Have to a good day ahead L=2m,d=3mm,A=

Answer: It is already rationalised Step-by-step explanation:Have to a good day ahead L=2m,d=3mm,A= 4

Answer: It is already rationalised Step-by-step explanation:Have to a good day ahead L=2m,d=3mm,A= 49π

Answer: It is already rationalised Step-by-step explanation:Have to a good day ahead L=2m,d=3mm,A= 49π

Answer: It is already rationalised Step-by-step explanation:Have to a good day ahead L=2m,d=3mm,A= 49π ×10

Answer: It is already rationalised Step-by-step explanation:Have to a good day ahead L=2m,d=3mm,A= 49π ×10 −6

Answer: It is already rationalised Step-by-step explanation:Have to a good day ahead L=2m,d=3mm,A= 49π ×10 −6 m

Answer: It is already rationalised Step-by-step explanation:Have to a good day ahead L=2m,d=3mm,A= 49π ×10 −6 m 2

Answer: It is already rationalised Step-by-step explanation:Have to a good day ahead L=2m,d=3mm,A= 49π ×10 −6 m 2

Answer: It is already rationalised Step-by-step explanation:Have to a good day ahead L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL=

Answer: It is already rationalised Step-by-step explanation:Have to a good day ahead L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 4

Answer: It is already rationalised Step-by-step explanation:Have to a good day ahead L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π

Answer: It is already rationalised Step-by-step explanation:Have to a good day ahead L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π

Answer: It is already rationalised Step-by-step explanation:Have to a good day ahead L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10

Answer: It is already rationalised Step-by-step explanation:Have to a good day ahead L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6

Answer: It is already rationalised Step-by-step explanation:Have to a good day ahead L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10

Answer: It is already rationalised Step-by-step explanation:Have to a good day ahead L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11

Answer: It is already rationalised Step-by-step explanation:Have to a good day ahead L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11

Answer: It is already rationalised Step-by-step explanation:Have to a good day ahead L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11 30×2

Answer: It is already rationalised Step-by-step explanation:Have to a good day ahead L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11 30×2

Answer: It is already rationalised Step-by-step explanation:Have to a good day ahead L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11 30×2 =8.48×10

Answer: It is already rationalised Step-by-step explanation:Have to a good day ahead L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11 30×2 =8.48×10 −5

Answer: It is already rationalised Step-by-step explanation:Have to a good day ahead L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11 30×2 =8.48×10 −5 m=0.085mm

Answer: It is already rationalised Step-by-step explanation:Have to a good day ahead L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11 30×2 =8.48×10 −5 m=0.085mm

Answer: It is already rationalised Step-by-step explanation:Have to a good day ahead L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11 30×2 =8.48×10 −5 m=0.085mm .

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