Math, asked by pooja3323, 1 year ago

rationalise 2-root 3 / root 3

Answers

Answered by LavishMittal
1
√3+√2 / √3-√2
=√3+√2 / √3-√2 × √3+√2 / √3+√2
=(√3+√2)² / (√3-√2) (√3+√2)
=3+2+2√6/3-2
=5+2√6/1
=5+2√6 hope it helps

pooja3323: if we have to put√3=1.732
pooja3323: sorry ure ans. is wrong
Answered by atreyee261
2

 \frac{2 -  \sqrt{3} }{  \sqrt{3} }  \\  =  \frac{ \sqrt{3} (2 -  \sqrt{3}) }{ \sqrt{3} }  \\  =  \frac{2 \sqrt{3} - 3 }{ \sqrt{3}  \times  \sqrt{3} }  \\  =  \frac{2 \sqrt{3}  - 3}{3}
hope this helps...

pooja3323: if we have to put√3= 1.732
atreyee261: then put 1.732 in place of √3 and calculate
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