Math, asked by priya23659, 1 year ago

rationalise 2-root 3/root 3​


Anonymous: ___k off

Answers

Answered by Anonymous
0

( √3 + √2 ) / ( √3 - √2 )

= [ (√3+√2)(√3+√2)]/[√3-√2)(√3+√2)]

= ( √3 + √2 )² / [ ( √3 )² - ( √2 )² ]

= [ (√3)² + ( √2)²+2×√3×√2 ] /( 3 - 2 )

[ By using ( a + b )² = a² + b² + 2ab ]

= ( 3 + 2 + 2√6 ) / 1

= 5 + 2√6

hope this answer helpful u

Answered by abdul9838
0

 \small \bf \pink{hey \: mate \: here \: is \: ur \: ans} \\  \\  \small \bf \pink{ \huge \: solution} \\  \\  \small \bf \pink{given \: that} \\  \\  \small \bf \pink{ \frac{2 -  \sqrt{3} }{ \sqrt{3} } } \\  \\  \small \bf \pink{ \frac{(2 -  \sqrt{3} ) \times  \sqrt{3} }{ \sqrt{3} \times  \sqrt{3}  } } \\  \\  \small \bf \pink{ \frac{2 \sqrt{3} - 3 }{3}  \:  \: ans}

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