rationalise 2-root 3/root 3
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( √3 + √2 ) / ( √3 - √2 )
= [ (√3+√2)(√3+√2)]/[√3-√2)(√3+√2)]
= ( √3 + √2 )² / [ ( √3 )² - ( √2 )² ]
= [ (√3)² + ( √2)²+2×√3×√2 ] /( 3 - 2 )
[ By using ( a + b )² = a² + b² + 2ab ]
= ( 3 + 2 + 2√6 ) / 1
= 5 + 2√6
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