Question

Rationalise
√24/√6-√3​

Answer 1

Answer:

To rationalize the denominator

✖ By root 24

The fraction is

6 root 24 / 72

I. e. Root 24 / 12

Step-by-step explanation:

Answer 2

$\green{\bold{\underline{ ☆ UPSC-ASPIRANT ☆} }}$

$\red{\bold{\underline{\underline{QUESTION:-}}}}$

Q:-Rationalise

√24/√6-√3

$\huge\tt\underline\blue{ANSWER }$

------>>>>Here is your answer<<<<--------

$⟹ \sqrt{24} = 2 \sqrt{6}$

$⟹ \frac{2 \sqrt{6} }{ \sqrt{6} - \sqrt{3} } \times \frac{ \sqrt{6} + \sqrt{3} }{ \sqrt{6} + \sqrt{3} }$

$⟹ \frac{2 \sqrt{6}( \sqrt{6} + \sqrt{3}) }{( { \sqrt{6} )}^{2} - { (\sqrt{3} )}^{2} } = \frac{12 + 2 \sqrt{6} \sqrt{3} }{6 - 3}$

$⟹ \frac{12 + 2 \sqrt{6} \sqrt{3} }{3} ✓$

HOPE IT HELPS YOU..

_____________________

Thankyou:)