Question

rationalise √3-1÷√3+1​

Answer 1

Step-by-step explanation:

$\frac{ \sqrt{3 } - 1}{ \sqrt{3} + 1} \times \frac{ \sqrt{3} - 1 }{ \sqrt{3} - 1} \\ = \frac{3 - \sqrt{3} \ - \sqrt{3} + 1 }{ {3} - 1} \\ = \frac{4 - 2 \sqrt{3} }{2} \\ = \frac{2 \times { \: \: \sqrt{3} - 1 } }{2} \\ = 2 - \sqrt{3}$

hence your answer is 2-root 3

Answer 2

$\huge \underline \mathbb {SOLUTION:-}$

Given:

• √3+1/√3-1

We need to rationalize the givenequation

To rationalize we will multiply and divide the denominator by √3+1

(√3+1)(√3+1)/(√3-1)(√3+1)

Denominator can be simplified using the identity (a2-b2)=(a-b)(a+b)

And the equation becomes

=( √3 + 1)²/(√3)2-(1)²

= (4+2√3)/2

= 2 + √3