rationalise√3-1÷√3+1
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HEY DEAR !!!
Here is ur answer --
√3 -1 / √3 + 1
= (√3 - 1 / √3 + 1 ) × ( √3 - 1 / √3 - 1 )
= (√3 - 1 )^2 / (√3)^2 - (1)^2
= [ (√3)^2 + (1)^2 - 2 × √3 × 1 ] / 3-1
= (3 + 1 - 2√3) / 2
= 4 - 2√3 / 2
Here is ur answer --
√3 -1 / √3 + 1
= (√3 - 1 / √3 + 1 ) × ( √3 - 1 / √3 - 1 )
= (√3 - 1 )^2 / (√3)^2 - (1)^2
= [ (√3)^2 + (1)^2 - 2 × √3 × 1 ] / 3-1
= (3 + 1 - 2√3) / 2
= 4 - 2√3 / 2
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