Question

Rationalise
3√2/√3+√6​

Answer 1

SOLUTION:-

$\frac{3 \sqrt{2} }{ \sqrt{3} + \sqrt{6}} = \frac{3 \sqrt{2} }{ \sqrt{3} + \sqrt{6} } \times \frac{ \sqrt{3} - \sqrt{6} }{ \sqrt{3} - \sqrt{6} }$

$\frac{3 \sqrt{2}( \sqrt{3} - \sqrt{6}) }{ {( \sqrt{3} )}^{2} - {( \sqrt{6} )}^{2} }$

$\frac{3 \sqrt{2} ( \sqrt{3} - \sqrt{6}) }{ - 3}$

$- \sqrt{2} ( \sqrt{3} - \sqrt{6} )$

$- \sqrt{6} + \sqrt{12}$

hope it helps you!!!‼️‼️✔✔✔

Answer 2

Answer:

$thank \: you$