Question

rationalise 3/4root5-root3

Answer 1

Hey friend,
Here is the answer you were looking for:
$\frac{3}{4 \sqrt{5} - \sqrt{3} } \\ \\ on \: rationalizing \: the \: denominator \: we \: get \\ \\ = \frac{3}{4 \sqrt{5} - \sqrt{3} } \times \frac{4 \sqrt{5} + \sqrt{3} }{4 \sqrt{5} + \sqrt{3} } \\ \\ using \: the \: identity \\ (a + b)(a - b) = {a}^{2} - {b}^{2} \\ \\ = \frac{3 \times 4 \sqrt{5} + 3 \times \sqrt{3} }{ {(4 \sqrt{5} )}^{2} - {( \sqrt{3} )}^{2} } \\ \\ = \frac{12 \sqrt{5} + 3 \sqrt{3} }{16 \times 5 - 3} \\ \\ = \frac{12 \sqrt{5} + 3 \sqrt{3} }{80 - 3} \\ \\ = \frac{12 \sqrt{5} + 3 \sqrt{3} }{77}$


Hope this helps!!!

@Mahak24

Thanks...
☺☺

Answer 2

here is your answer friend