Rationalise 3 by 3 root 5 plus root 2
Answers
Answered by
0
Answer:
By the given data
\frac{3}{\sqrt{5}+\sqrt{2} }5+23 Rationalizing the denominator
\frac{3(\sqrt{5}-\sqrt{2} ) }{(\sqrt{5}+\sqrt{2})(\sqrt{5}-\sqrt{2}) }(5+2)(5−2)3(5−2) Multiplying and dividing with \sqrt{5} -\sqrt{2}5−2 since it is the Rationalizing factor.
We get;
\frac{3(\sqrt{5} -\sqrt{2} ) }{3}33(5−2)
Therefore our final answer is \sqrt{5} -\sqrt{2}5−2
I think this is the answer. Hope this is helpful.
Answered by
0
Answer:
(9√5-3√2)/43
Step-by-step explanation:
3/(3√5+√2)
={3×(3√5-√2)}/(3√5+√2)(3√5-√2)
=(9√5-3√2)/(3√5)²-(√2)² [a²-b²=(a+b)(a-b)]
=(9√5-3√2)/45-2
=(9√5-3√2)/43
Hope it helps!
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