Math, asked by CIZU, 1 month ago

Rationalise 3 by 3 root 5 plus root 2

Answers

Answered by Nivlem
0

Answer:

By the given data  

\frac{3}{\sqrt{5}+\sqrt{2} }5+23 Rationalizing the denominator

\frac{3(\sqrt{5}-\sqrt{2} ) }{(\sqrt{5}+\sqrt{2})(\sqrt{5}-\sqrt{2}) }(5+2)(5−2)3(5−2)    Multiplying and dividing with \sqrt{5} -\sqrt{2}5−2 since it is the Rationalizing factor.

We get;

\frac{3(\sqrt{5} -\sqrt{2} ) }{3}33(5−2)

Therefore our final answer is \sqrt{5} -\sqrt{2}5−2

I think this is the answer. Hope this is helpful.

Answered by prajnalisarisa
0

Answer:

(9√5-3√2)/43

Step-by-step explanation:

3/(3√5+√2)

={3×(3√5-√2)}/(3√5+√2)(3√5-√2)

=(9√5-3√2)/(3√5)²-(√2)² [a²-b²=(a+b)(a-b)]

=(9√5-3√2)/45-2

=(9√5-3√2)/43

Hope it helps!

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