Question

rationalise 3 root 2 + 1 / 2 root 5 - 3

Answer 1

AnSwEr

${\tt{\red{\underline{\large{Given}}}}}$

• A term

$\tt\dfrac{3\sqrt{2}+1}{2\sqrt{5}-3}$

${\sf{\green{\underline{\large{To\:find}}}}}$

• Rationalise the denominator

${\sf{\pink{\underline{\Large{Explanation}}}}}$

$\tt\dfrac{3\sqrt{2}+1}{2\sqrt{5}-3}$

Step by step solution

$\tt\dfrac{3\sqrt{2}+1}{2\sqrt{5}-3}$

$\rightarrow\tt\dfrac{3\sqrt{2}+1}{2\sqrt{5}-3}\times\dfrac{2\sqrt{5}+3}{2\sqrt{5}+3}$

=>(3√2+1)(2√5+3) / 11

=>3√2(2√5+3)1(2√5+3)

=>(6√10+9√2+2√5+5 )/ 11

Hence the rationalisations is (6√10+9√2+2√5+5 )/ 11

Answer 2

Answer:

=>(3√2+1)(2√5+3) / 11

=>3√2(2√5+3)1(2√5+3)

=>(6√10+9√2+2√5+5 )/ 11