Question

rationalise 4√3/√6-√2​

Answer 1

Answer:

here is ur answer

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Answer 2

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$\frac{4 \sqrt{3} }{6 - \sqrt{2} } \\ \\ = > \frac{4 \sqrt{3} (6 + \sqrt{2} )}{(6 - \sqrt{2})(6 + \sqrt{2}) } \\ \\ = > \frac{24 \sqrt{3} + 4 \sqrt{6} }{ {6}^{2} - { (\sqrt{2} )}^{2} } \\ \\ = > \frac{24 \sqrt{3} + 4 \sqrt{6}}{36 - 2} \\ \\ = > \frac{ \: 24 \sqrt{3} + 4 \sqrt{6}}{34} \\ \\ = > \frac{2(12 \sqrt{3} + 2 \sqrt{6} ) }{34} \\ \\ = > \frac{12 \sqrt{3} + 2 \sqrt{6} }{17}$