Math, asked by bijithjr10, 4 months ago

rationalise 4√3/√6-√2​

Answers

Answered by bhoomikabisht1402
1

Answer:

here is ur answer

hope it help :)

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Answered by xSoyaibImtiazAhmedx
2

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 \frac{4 \sqrt{3} }{6 -  \sqrt{2} }  \\   \\  =  >  \frac{4 \sqrt{3} (6 +  \sqrt{2} )}{(6 -  \sqrt{2})(6  +  \sqrt{2})  }  \\  \\  =  >  \frac{24 \sqrt{3} + 4 \sqrt{6}  }{ {6}^{2} -  { (\sqrt{2} )}^{2}  }  \\  \\  =  >  \frac{24 \sqrt{3} + 4 \sqrt{6}}{36 - 2}  \\  \\   =  >  \frac{ \: 24 \sqrt{3} + 4 \sqrt{6}}{34}  \\  \\  =  >  \frac{2(12 \sqrt{3}  + 2 \sqrt{6} ) }{34}  \\  \\  =  >  \frac{12 \sqrt{3}  + 2 \sqrt{6} }{17}

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