Question

rationalise 4 *route18/route12 -8 *route75/route35 + 9* route2/ route3?... plz solve it!​

Answer 1

$= > \frac{4 \sqrt{18} }{ \sqrt{12} } - \frac{8 \sqrt{75} }{ \sqrt{35} } + \frac{9 \sqrt{2} }{ \sqrt{3} } \\ \\ = > \frac{4 \times 3 \sqrt{2} }{2 \sqrt{3} } - \frac{8 \times 5 \sqrt{3} }{ \sqrt{35} } + \frac{9 \sqrt{2}}{ \sqrt{3} } \\ \\ = > \frac{12 \sqrt{2} }{2 \sqrt{3} } - \frac{40 \sqrt{3} }{ \sqrt{35} } + \frac{9 \sqrt{2} }{ \sqrt{3} }$

$= > \frac{12 \sqrt{2} }{2 \sqrt{3} } + \frac{9 \sqrt{2} }{ \sqrt{3} } - \frac{40 \sqrt{3} }{ \sqrt{35} } \\ \\ = > \frac{12 \sqrt{2} + 18 \sqrt{2} }{2 \sqrt{3} } - \frac{40 \sqrt{3} }{ \sqrt{35} } \\ \\ = > \frac{30 \sqrt{2} }{2 \sqrt{3} } - \frac{40 \sqrt{3} }{ \sqrt{35} }$

Hope it's helpful to you