rationalise 5/ √3-√5
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5
√3-√5
5 × √3+√5
√3-√5 √3+√5
5×(√3+√5)
(√3)²-(√5)² As{ (a+b)(a-b)= a²-b²}
5×√5+√3
3 - 5
5×√5+√3
-2
-5 (√5+√3)
2
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