Question

rationalise 5 root 3-4 root 2/4 root 3 +3root 2

Answer 1

Hey friend,
Here is the answer you were looking for:
$\frac{5 \sqrt{3} - 4 \sqrt{2} }{4 \sqrt{3} + 3 \sqrt{2} } \\ \\ \: on \: rationalizing \: we \: get \\ \\ \frac{5 \sqrt{3} - 4 \sqrt{2} }{4 \sqrt{3} + 3 \sqrt{2} } \times \frac{4 \sqrt{3} - 3 \sqrt{2} }{4 \sqrt{3} - 3 \sqrt{2} } \\ \\ = \frac{5 \sqrt{3} \times 4 \sqrt{3} - 5 \sqrt{3} \times 3 \sqrt{2} - 4 \sqrt{2} \times 4 \sqrt{3} + 4 \sqrt{2} \times 3 \sqrt{2}}{ {(4 \sqrt{3})^{2} - {(3 \sqrt{2} )}^{2} } } \\ \\ = \frac{60 - 15 \sqrt{6} - 16 \sqrt{6} + 24}{48 - 18} \\ \\ = \frac{84 - 31 \sqrt{6} }{30}$

Hope this helps!!!

@Mahak24

Thanks...
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