Math, asked by Sanju1616, 1 year ago

rationalise 7-3✓2÷7+3✓2

Answers

Answered by Anonymous
2
Heya!


Here is yr answer.....



 =  >  \frac{7 - 3 \sqrt{2} }{7 + 3 \sqrt{2} }  \\  \\  =  >  \frac{7 - 3 \sqrt{2} }{7 + 3 \sqrt{2} }  \times  \frac{7 - 3 \sqrt{2} }{7 - 3 \sqrt{2} }  \\  \\  =  >  \frac{(7 - 3 \sqrt{2)} ^{2} }{(7 + 3 \sqrt{2)}(7 -  - 3 \sqrt{2} ) } \\  \\  =  >  \frac{7 ^{2}  - 2(7)(3 \sqrt{2)} + (3 \sqrt{2)}^{2} }{ {7}^{2} - (3 \sqrt{2} )^{2}  }  \\  \\  =  >  \frac{49 - 42  \sqrt{2}  + 18 }{49 - 18}  \\  \\  =  >  \frac{67 - 42 \sqrt{2} }{31}


Hope it hlpz.....
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