Math, asked by rathoregunjan911, 10 months ago

rationalise 7+3under root 2 upon 7-3under root 2​

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Answered by ritika21012001
0

Answer:

Hope this will help you

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Answered by 0ShivankPandey0
0

=(7+3√2)/(7-3√2)

=(7+3√2)/(7-3√2)X(7+3√2)/(7+3√2)

=(7+3√2)²/(7)²-(3√2)²

=(49+18+42√2)/(49)-(18)

=(67+42√2)/(31)

SAMAJ AAYA.

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