rationalise denomination 3√5+√3/√5-√3
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(3√5+√3)/(√5-√3)
=(3√5+√3)(√5+√3)÷[(√5+√3)(√5-√3)]
=[15+3√15+√15+3]÷[2]
=[18+4√15]/2
=[9+2√15]
hope it helps you
@di
=(3√5+√3)(√5+√3)÷[(√5+√3)(√5-√3)]
=[15+3√15+√15+3]÷[2]
=[18+4√15]/2
=[9+2√15]
hope it helps you
@di
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