Question

rationalise it 7√3-5√2÷√48+√18​

Answer 1

Answer:

7root3-5root2

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4root3-3root2

(7root3-5root2)(4root3+3root2)

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16 ×3-9×2

Answer 2

Answer:

The answer is 114 - 7 root54 - 5 root96/30

Step-by-step explanation:

To rationalize the number given in the question

Step 1 = Multiply both the numerator and the denominator of the number with the conjugate of the denominator(root48 + root18)

The conjugate of the denominator is (root48 - root18)

So,

= 7 root3 - 5 root2/root48 + root18 X root48 - root18/root48 - root18

= (7 root3 - 5 root2)(root48 - root18)/(root 48 + root18)(root48 - root18)

Step 2 = Follow the identity and multiply the numbers

= 7 root3 X root48 - 7 root3 X root18 - 5 root2 X root48 + 5 root2 X root18[using distributive property of multiplication]/(root48)^2 - (root18)^2[using identity a^2 - b^2 = (a + b)(a - b)]

= 7 root144 - 7 root54 - 5 root96 + 5 root36/48 - 18

= 7 X 12(12^2 = 144) + 5 X 6(6^2 = 36) - 7 root54 - 5 root96/30

= 84(7 X 12) + 30(6 X 5) - 7 root54 - 5 root96/30

= 114 - 7 root54 - 5 root96/30