rationalise (root 2-root3)÷(2root3-5root2)
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Answer:
√2-√3/2·√3 - 5√2
√2-√3(2√3 + 5√2) / (2√3)² - (5√2)²
2√6+4+5√10
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Step-by-step explanation:
=(sqrt (2)-sqrt (3))/(2*sqrt (3)-5*sqrt (2))
=((sqrt(2)-sqrt(3))*(2*sqrt(3)+5*sqrt(2)))/4*3-25*4
=2*sqrt(6)+10-6+5sqrt(6)/-88
=-(4+7*sqrt(6))/88
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