Question

rationalise :- root 3-1 over root 3 + 1 = a + b root 3

Answer 1

Hey friend,

Here is your answer,
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$\frac{\sqrt3 - 1}{\sqrt3 +1}$

=> $\frac{\sqrt3 - 1}{\sqrt3 +1} * \frac{\sqrt3-1}{\sqrt3 -1}$

=> $\frac {(\sqrt3 -1)^2}{(\sqrt3+1)(\sqrt3 -1)}$

=> $\frac{3 + 1 - 2\sqrt3}{(\sqrt3)^2 - 1^2}$

=> $\frac{4+2\sqrt3}{3-1}$

=> $\frac {2(2+\sqrt3)}{2}$

=> $2+\sqrt3$

=> $2+\sqrt3$ = a+b$\sqrt3$

Hence a = 2 and b=1

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Answer 2

Answer:

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