Question

rationalise surds denominator 2/3+√5

Answer 1

Answer:

$\displaystyle\frac2{3+\sqrt5} = \frac{2(3-\sqrt5)}{(3+\sqrt5)(3-\sqrt5)}\\\\=\frac{2(3-\sqrt5)}{3^2-(\sqrt5)^2}\\\\=\frac{2(3-\sqrt5)}{9-5}\\\\=\frac{2(3-\sqrt5)}4\\\\=\frac{3-\sqrt5}{2}$