Question

rationalise
$\frac{1}{7 + 3 \sqrt{2} }$
​

Answer 1

Answer:

$\frac{1}{7 + 3 \sqrt{2} }$

$= \frac{1}{7 + 3 \sqrt{2} } \times \frac{7 - 3 \sqrt{2} }{7 - 3 \sqrt{2} }$

$= \frac{7 - 3 \sqrt{2} }{(7) {}^{2} - (3 \sqrt{2} ) {}^{2} }$

$= \frac{7 - 3 \sqrt{2} }{49 - 18}$

$= \frac{7 - 3 \sqrt{2} }{31}$

Answer 2

Step-by-step explanation:

see attatchment

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