Math, asked by pokemon214, 5 months ago

rationalise
 \frac{2 +  \sqrt{3} }{2 -  \sqrt{3} }

Answers

Answered by Anonymous
53

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Q:-rationalise

 \frac{2 + \sqrt{3} }{2 - \sqrt{3} }

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------>>>>Here is your answer<<<<--------

 \frac{2 +  \sqrt{3} }{2 -  \sqrt{3} }  \times  \frac{2 +  \sqrt{3} }{2 +  \sqrt{3} }

 \frac{( {2 +  \sqrt{3}) }^{2} }{ ({2})^{2}  -  { (\sqrt{3}) }^{2}  }

 \frac{( {2})^{2} +  {( \sqrt{3}) }^{2} + 2(2)( \sqrt{3}  ) }{4 - 3}

 = 4 + 3 + 4 \sqrt{3}  = 7 + 4 \sqrt{3} ✓

HOPE IT HELPS YOU..

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Thankyou:)

Answered by Anonymous
0
Answer is :-4+3+4√3=7+4√3.

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