Math, asked by harsh2710, 10 months ago

Rationalise
 \frac{2 \sqrt{6 } -  \sqrt{5}  }{3 \sqrt{5} - 2 \sqrt{6 }  }


harsh2710: rationalise it

Answers

Answered by Anonymous
3

 \frac{2 \sqrt{6} -  \sqrt{5}  }{3 \sqrt{5} - 2 \sqrt{6}  }  \times  \frac{3 \sqrt{5}   + 2 \sqrt{6} }{3 \sqrt{5} + 2 \sqrt{6}  }  \\  \\  =  >  \frac{6 \sqrt{30}  + 24 - 15 - 2 \sqrt{30} }{45 - 24}  \\  \\  =  >  \frac{4 \sqrt{30}  + 9}{21}


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Answered by Anonymous
1

 \frac{2 \sqrt{6}  -  \sqrt{5} }{3 \sqrt{5} - 2 \sqrt{6}  }

2√6-√5*3√5+2√6/3√5-2√6*3√5+2√6

6√30-3√25+4√36-2√30/(3√5)²-(2√6)²

6√30-3*5+4*6-2√30/9*5-4*6

6√30-2√30-15+24/45-24

4√30+9/21

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