Math, asked by manish2642, 1 year ago

Rationalise th√10-√5÷√2

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Answered by nehakamal

$\sqrt{10 \: \: \: - } \sqrt{5} \div \sqrt{2} \\$

$\sqrt{10} - \sqrt{5} \times \sqrt{2} \div \sqrt{2} \times \sqrt{2}$

$\sqrt{20} - \sqrt{10} \div 2$

nehakamal: if u want u can further simplify

Answered by abdul9838

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$\huge \: Hola \\ \\ Hey \: dude \: here \: is \: Ans \\ \\ \huge \: Question \\ \\ \underline{Rationalise \: the \: denominator }\\ \\ \huge \: Answer \\ \\ \bf \: \frac{ \sqrt{10} - \sqrt{5} }{ \sqrt{2} } \\ \\ \bf \: \frac{( \sqrt{10} - \sqrt{5}) \sqrt{2} }{ \sqrt{2} \times \sqrt{2} } \\ \\ \bf \: \frac{ (\sqrt{10} - \sqrt{5}) \sqrt{2} }{2} \\ \\ \bf \: \frac{ \sqrt{20} - \sqrt{10} }{2} \\ \\ \bf \: \frac{ \sqrt{10}( \sqrt{2} - 1) }{2} \: \: ans$

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$\huge \: Thanks \: for \: asking. \\ \\ \underline{Abdul \: is \: here }\\ \\ \huge \: Follow \: me.$

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