Question

rationalise the above no​

Answer 1

Answer :

$\frac{3 - 2 \sqrt{2} }{3 + 2 \sqrt{2} } \\ \\ \frac{3 - 2 \sqrt{2} }{3 + 2 \sqrt{2} } \times \frac{3 - 2 \sqrt{2} }{3 - 2 \sqrt{2} } \\ \\ \frac{(3 - 2 \sqrt{2}) {}^{2} }{(3) {}^{2} - (2 \sqrt{2}) {}^{2}} \\ \\ \frac{(3) {}^{2} - 2 \times 3 \times 2 \sqrt{2} + (2 \sqrt{2}) {}^{2} }{9 - 8} \\ \\ \frac{9 - 12 \sqrt{2} + 8}{1} \\ \\ \boxed{ \red{ \sf 17 - 12 \sqrt{2}}}$

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Answer 2

$\frac{3 - 2\sqrt{2} }{3 + 2 \sqrt{2} } \\ = \frac{3 - 2\sqrt{2} }{3 + 2 \sqrt{2} } \times \frac{3 - 2 \sqrt{2} }{3 - 2 \sqrt{2} } \\ = \frac{(3 - 2 \sqrt{2} )^{2} }{9 - 8} \\ = \frac{9 - 12 \sqrt{2} + 8}{1} \\ = 17 - 12 \sqrt{2} \: ans$

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