Question

Rationalise the deno minator of 3/√7+√4

Answer 1

Answer:

$= \frac{3}{ \sqrt{7} + \sqrt{4} } \times \frac{ \sqrt{7} - \sqrt{4} }{ \sqrt{7} - \sqrt{4} } \\ \\ = \frac{3( \sqrt{7} - \sqrt{4} )}{ {( \sqrt{7}) }^{2} - {( \sqrt{4} )}^{2} } \\ \\ = \frac{3 (\sqrt{7} -\sqrt{4} ) }{7 - 4} \\ \\ = \frac{3 (\sqrt{7} -\sqrt{4} ) }{3} \\ \\ = \sqrt{7 } - \sqrt{4} \\\\=\sqrt{7}-2$

Answer 2

Answer:

Multiply the numerator and denominator with ( √7 - √4 ) to rationalize it.

= 3(√7 - √4 ) ÷ ( √7 + √4 ) ( √7 - √4 )

= 3(√7 - √4 ) ÷ { (√7)² - (√4)² }

= 3(√7 - √4 ) ÷ ( 7 - 4 )

= 3(√7 - √4 ) ÷ 3

= 3(√7 - √4 ) × 1/3

= (√7 - √4)

Hope it will help you....