Math, asked by jyotimmm, 1 year ago

Rationalise the denomenator- 7+3√5/ 7-3√5

Answers

Answered by Aurora34
13

 = \frac{7 + 3 \sqrt{5}}{7 -3 \sqrt{5}  }  \\  \\  = \frac{7 + 3 \sqrt{5}}{7 -3 \sqrt{5}  }  \times  \frac{7 + 3 \sqrt{5} }{7 + 3 \sqrt{5} }  \\  \\  =  \frac{( {7 + 3 \sqrt{5}) }^{2} }{49 - 45}  \\  \\  =  \frac{49 + 45 + 42 \sqrt{5} }{4}  \\  \\  =  \frac{94 + 42 \sqrt{5}  }{4}  \\  \\  =  \frac{2(47 + 21 \sqrt{5}) }{4}  \\   \\  =  \frac{47 + 21 \sqrt{5} }{2}

Rajkumargupta4: Hii
Noah11: great answer mam!
Aurora34: thnx
Noah11: :)
Rajkumargupta4: hiii mc
jyotimmm: hii
Rajkumargupta4: happy independence day
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