Math, asked by nagunagamani8813, 7 months ago

Rationalise the denominate
5by√3-√5

Answers

Answered by PharohX
3

Answer:

 \frac{5}{ \sqrt{3} -  \sqrt{5}  }  \\ \\   =  \frac{5}{ \sqrt{3} -  \sqrt{5}  }  \times  \frac{ \sqrt{3} + \sqrt{5}   }{ \sqrt{3} +  \sqrt{5}  }  \\  \\  =  \frac{5( \sqrt{3} +  \sqrt{5}  )}{( \sqrt{3}) {}^{2} - ( \sqrt{5}) {}^{2}    }  \\  \\  =  \frac{5( \sqrt{3}  +  \sqrt{5} )}{3 - 5}  \\  \\  =   - \frac{5( \sqrt{3}  +  \sqrt{5})  }{2}

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