Math, asked by psethi, 1 year ago

Rationalise the denominater of 1 / √7-√3

Answers

Answered by vivek2001

[tex]\frac{1}{ \sqrt{7}- \sqrt{3} } =\frac{1}{ \sqrt{7}- \sqrt{3} } * \frac{ \sqrt{7}+ \sqrt{3} }{ \sqrt{7} + \sqrt{3} } = \frac{ \sqrt{7} + \sqrt{3} }{( \sqrt{7}+ \sqrt{3}) ^{2} } = \frac{ \sqrt{7}+ \sqrt{3} }{(7+3)} =\frac{ \sqrt{7}+ \sqrt{3} }{10} [/tex]

psethi: sorrY Yrr but option hi ni aa ra

badhri: 1/√7-√3 * (√7+√3)/√7+√30
=(√7+√3)/(√7)²-(√3)²
=(√7+√3)/ (7-3)
=(√7+√3) /4

vivek2001: kya?????

vivek2001: sethi bhai kiska right hai

vivek2001: jaldi bol bhai

psethi: Arre Yrr tune denominator me plus kiYA h n usne subta

psethi: *subract

psethi: to me kYa btAau

psethi: vese Yrr sorrY but uska sahi h

psethi: cOz tune siGn ni chanGe kiYe

Answered by badhri

1/√7-√3 * (√7+√3)/√7+√30
=(√7+√3)/(√7)²-(√3)²
=(√7+√3)/ (7-3)
=(√7+√3) /4

badhri: vivek answer is right but denominator is 4

vivek2001: noooo

vivek2001: look carefully

badhri: denominator is 7-3 = 4

badhri: formula is a² - b² = (a+b )(a-b)

badhri: what happened

psethi: hmm Yrr vivek he is riGht

Previous Question

Next Question