Rationalise the denominater of 1 / √7-√3
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2
[tex]\frac{1}{ \sqrt{7}- \sqrt{3} }
=\frac{1}{ \sqrt{7}- \sqrt{3} } * \frac{ \sqrt{7}+ \sqrt{3} }{ \sqrt{7} + \sqrt{3} }
= \frac{ \sqrt{7} + \sqrt{3} }{( \sqrt{7}+ \sqrt{3}) ^{2} }
= \frac{ \sqrt{7}+ \sqrt{3} }{(7+3)}
=\frac{ \sqrt{7}+ \sqrt{3} }{10}
[/tex]
psethi:
sorrY Yrr but option hi ni aa ra
1/√7-√3 * (√7+√3)/√7+√30
=(√7+√3)/(√7)²-(√3)²
=(√7+√3)/ (7-3)
=(√7+√3) /4
=(√7+√3)/(√7)²-(√3)²
=(√7+√3)/ (7-3)
=(√7+√3) /4
kya?????
sethi bhai kiska right hai
jaldi bol bhai
Arre Yrr tune denominator me plus kiYA h n usne subta
*subract
to me kYa btAau
vese Yrr sorrY but uska sahi h
cOz tune siGn ni chanGe kiYe
Answered by
2
1/√7-√3 * (√7+√3)/√7+√30
=(√7+√3)/(√7)²-(√3)²
=(√7+√3)/ (7-3)
=(√7+√3) /4
=(√7+√3)/(√7)²-(√3)²
=(√7+√3)/ (7-3)
=(√7+√3) /4
vivek answer is right but denominator is 4
noooo
look carefully
denominator is 7-3 = 4
formula is a² - b² = (a+b )(a-b)
what happened
hmm Yrr vivek he is riGht
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