Question

rationalise the denominater of 2√7/1+√2​

Answer 1

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Answer 2

Answer:

Answer is $=2\sqrt{7}(\sqrt{2}-1)$

Step-by-step explanation:

$\frac{2\sqrt{7} }{1+\sqrt{2}}\\\\=\frac{2\sqrt{7} }{1+\sqrt{2}}\times\frac{1-\sqrt{2}}{1-\sqrt{2}}\\\\=\frac{2\sqrt{7}-2\sqrt{14}}{1-2} \\\\=\frac{2\sqrt{7}-2\sqrt{14}}{-1} \\\\=2\sqrt{14}-2\sqrt{7}\\\\=2\sqrt{7}(\sqrt{2}-1)$